Solve urllib.error.URLError urlopen error Errno 11004 getaddrinfo failed

Table of Contents

Solve urllib.error.URLError urlopen error Errno 11004 getaddrinfo failed

wrong reason

solution

1. Check the correctness of the URL

2. Check network connection

3. Use IP address instead of hostname

4. Use other network libraries

in conclusion

function definition

function function

Usage example

Solving urllib.error.URLError urlopen error Errno 11004 getaddrinfo failed

When doing web development or network data crawling, you may encounter errors such as ??urllib.error.URLError: urlopen error [Errno 11004] getaddrinfo failed??. This error means that the ??urlopen?? function cannot obtain the correct host name and IP address when parsing the URL. This blog will help you understand the cause of this error and provide a solution.

Error reason

This error is usually caused by one of the following reasons:

  1. DNS resolution error: The correct host name cannot be resolved through the URL.
  2. Network connection problem: Unable to connect to the host or unable to complete the network request.

Solution

1. Check the correctness of the URL

First, make sure your URL is correct and accessible. There may be misspellings, missing protocol headers (such as ??http://??, ??https://??) or other formatting issues in the URL . Use a browser to access the URL and see if you can open the web page or obtain data normally.

2. Check network connection

You may be experiencing network connectivity issues that prevent you from connecting to the target host. Try the following methods to troubleshoot and fix network issues:

  • Check if the network connection is working properly. Make sure your computer is connected to the Internet and try connecting to other websites or services to see if you can access them.
  • Check firewall settings. Certain firewalls or security software may block your program from accessing the network. Make sure your program is allowed through the firewall.
  • Check proxy server configuration. If you are using a proxy server for your network connection, make sure it is configured correctly and that the proxy server is working properly.

3. Use IP address instead of host name

If there are problems with DNS resolution, you can try using the IP address instead of the hostname. Open a command line terminal and use the ??ping?? command to obtain the IP address of the target host:

bashCopy coding example.com

Replace ??example.com?? with your target hostname. In the output, you will find the IP address of the target host. Use this IP address for your URL and try running the program again.

pythonCopy codeimport urllib.request
url = 'http://<ip_address>/path/to/resource'
response = urllib.request.urlopen(url)
data = response.read()

???? is the IP address you obtained from the ??ping?? command.

4. Use other network libraries

If you still can’t solve the problem after trying the above solutions, you can try to use other Python network libraries, such as the ??requests?? library, which provides a simpler and stable API:

pythonCopy codeimport requests
url = 'http://example.com/path/to/resource'
response = requests.get(url)
data = response.text

Make sure to install other network libraries before using them. You can use ??pip?? to install:

bashCopy codepip install requests

Conclusion

??urllib.error.URLError: urlopen error [Errno 11004] getaddrinfo failed??The error indicates that a problem occurred during URL parsing or network connection. You can resolve this error by checking that the URL is correct, troubleshooting network connectivity issues, using IP addresses instead of hostnames, and trying other networking libraries. Choose the appropriate solution based on the specific situation and ensure that your program can properly access the URL and obtain the required data. I hope this blog can help you solve the ??URLError?? error and smoothly carry out network data crawling and web development. I wish you success!

When encountering the ??urlopen error [Errno 11004] getaddrinfo failed?? error, we take the actual application scenario of crawling a web page as an example to give sample code.

pythonCopy codeimport urllib.request
#Define URL
url = 'http://www.example.com'
try:
    # Use the urllib library to send HTTP requests
    response = urllib.request.urlopen(url)
    data = response.read()
    #Print web page content
    print(data.decode('utf-8'))
except urllib.error.URLError as e:
    print("An error occurred:", e)

In this example, we define the URL of the web page to be crawled as ‘http://www.example.com’. We use the `urlopen` function to send an HTTP request, and then use the `read` method to get the response content. Finally, we print the content in UTF-8 encoding. If you encounter the ??urlopen error [Errno 11004] getaddrinfo failed?? error, you can make appropriate modifications based on the previously provided solutions. For example, we can try using the IP address instead of the hostname:

pythonCopy codeimport urllib.request
# Use IP address instead of hostname
ip_address = '127.0.0.1'
url = f'http://{ip_address}'
try:
    # Use the urllib library to send HTTP requests
    response = urllib.request.urlopen(url)
    data = response.read()
    #Print web page content
    print(data.decode('utf-8'))
except urllib.error.URLError as e:
    print("An error occurred:", e)

In this example, we define an IP address (127.0.0.1) and replace it in the URL. We then send an HTTP request using the modified URL, get the response content and print it out. Of course, in actual applications, other error handling and exception handling may be required, as well as further parsing and processing of web page content. The sample code here only helps you understand the ideas and basic code structure for solving errors. Specific application scenarios and code logic will vary based on actual needs.

??urlopen?? is a function in the urllib library in Python, used to send HTTP requests and get responses.

function definition

??urlopen(url, data=None, [timeout, ]*, cafile=None, capath=None, cadefault=False, context=None)??

  • ??url??: URL address to send the request.
  • ??data??: The data to be sent. Default is None.
  • ??timeout??: Timeout time, unit is seconds. The default is the socket’s default timeout.
  • ??cafile??: The file path containing the CA certificate. Default is None.
  • ??capath??: Directory path containing the CA certificate. Default is None.
  • ??cadefault??: Determine whether to use the default CA certificate. Default is False.
  • ??context??: SSL context. Default is None.

Function function

The function of the ??urlopen?? function is to send an HTTP request and obtain a response. It can send different types of requests such as GET and POST, and can set parameters such as timeout and verification certificate.

Usage example

The following is an example of using the ??urlopen?? function to send a GET request:

pythonCopy codeimport urllib.request
#Define URL
url = 'http://www.example.com'
try:
    #Send HTTP request and get response
    response = urllib.request.urlopen(url)
    # Read the response content
    data = response.read()
    #Print response content
    print(data.decode('utf-8'))
except urllib.error.URLError as e:
    print("An error occurred:", e)

In this example, we first define a URL, then use the urlopen function to send an HTTP request and store the response in the response object . Next, we use the ??read?? method to read the response content and the ??decode?? method to decode the byte stream into a string. Finally, we print out the decoded content. In addition to sending GET requests, the ??urlopen?? function can also send different types of requests such as POST. The specific usage methods and parameter settings will vary and can be adjusted according to actual needs. It should be noted that the ??urlopen?? function may also throw a ??URLError?? exception, indicating that an error occurred during the request process, such as network connection Questions etc. Therefore, when using the ??urlopen?? function, it is best to use the exception handling mechanism to catch possible exceptions and execute corresponding error handling logic.