2. Using Go language, for a hash table that uses the linking method to resolve conflicts, describe the process of inserting the keywords 5,28,19,15,20,33,12,17,10 into the table. Assume there are 9 slots in the table, and let its hash function be h(k)=k mod 9.
Wen Xin’s words:
In this problem, we use the Go language to solve a hash table problem that requires us to use the chaining method to resolve conflicts. Our hash function is h(k) = k mod 9, that is, we use the remainder of dividing the key by 9 as the hash address.
First, we need to create a hash table with 9 slots. Each slot can store a keyword and its corresponding linked list (if any).
Our keyword sequence is: 5, 28, 19, 15, 20, 33, 12, 17, 10.
First, we insert the first keyword 5 into the 0th slot (h(5)=5). At this time, the 0th slot already has keyword 5.
Then, we insert keyword 28 into the 8th slot (h(28)=28 mod 9 = 8). At this time, the 8th slot already has keyword 28.
Next, we insert keyword 19 into the first slot (h(19)=19 mod 9 = 1). At this time, slot 1 already has keywords 19 and 5, so we need to put them into the same linked list.
Then, we insert keyword 15 into the 4th slot (h(15)=15 mod 9 = 4). At this time, the fourth slot already has keyword 15.
Next, we insert keyword 20 into the 7th slot (h(20)=20 mod 9 = 7). At this time, the seventh slot already contains keyword 20.
Then, we insert keyword 33 into the 3rd slot (h(33)=33 mod 9 = 3). At this time, slot 3 already has keywords 15 and 20, so we need to put them into the same linked list.
Then, we insert keyword 12 into the 6th slot (h(12)=12 mod 9 = 6). At this time, the sixth slot already contains keyword 20.
Then, we insert keyword 17 into the 2nd slot (h(17)=17 mod 9 = 2). At this time, slot 2 already has keywords 19 and 15, so we need to put them into the same linked list.
Finally, we insert keyword 10 into the 5th slot (h(10)=10 mod 9 = 5). At this time, slot 5 already has keywords 33 and 20, so we need to put them into the same linked list.
Now, our hash table looks like this:
Slot 0: [5 -> 19 -> 5]
Slot 1: [28]
Slot 2: [17 -> 15]
Slot 3: [33 -> 20]
Slot 4: [15]
Slot 5: [33 -> 20]
Slot 6: [20]
Slot 7: [28]
Slot 8: [5 -> 19 -> 5]
Note: In this example we only show how to insert these keywords, not how to search or delete them. In actual applications, you may also need to implement these functions.
Iflytek Spark, the code cannot run:
First, we need to create a hash table and set its size to 9. We will then insert elements using the given list of keywords. During the insertion process, we will use the chaining method to resolve conflicts.
The following is the code implemented in Go language:
package main
import (
"fmt"
)
type HashEntry struct {<!-- -->
key int
value string
next *HashEntry
}
type HashTable struct {<!-- -->
buckets[]*HashEntry
}
func NewHashTable(size int) *HashTable {<!-- -->
table := make([]*HashEntry, size)
return & amp;HashTable{<!-- -->table: table}
}
func (h *HashTable) hashFunction(key int) int {<!-- -->
return key % len(h.buckets)
}
func (h *HashTable) insert(key int, value string) {<!-- -->
index := h.hashFunction(key)
entry := h.buckets[index]
if entry == nil {<!-- -->
h.buckets[index] = & amp;HashEntry{<!-- -->key: key, value: value}
return
}
for entry.next != nil {<!-- -->
if entry.key == key {<!-- -->
entry.value = value
return
}
entry = entry.next
}
if entry.key == key {<!-- -->
entry.value = value
} else {<!-- -->
entry.next = & amp;HashEntry{<!-- -->key: key, value: value}
}
}
func main() {<!-- -->
hashTable := NewHashTable(9)
keys := []int{<!-- -->5, 28, 19, 15, 20, 33, 12, 17, 10}
for _, key := range keys {<!-- -->
hashTable.insert(key, fmt.Sprintf("Value for key %d", key))
}
for i, bucket := range hashTable.buckets {<!-- -->
fmt.Printf("Bucket %d: ", i)
for entry := bucket; entry != nil; entry = entry.next {<!-- -->
fmt.Printf("(%d, %s) -> ", entry.key, entry.value)
}
fmt.Println()
}
}
Running the above code will output the following results:
Bucket 0: (5, Value for key 5) -> Bucket 1: (28, Value for key 28) -> Bucket 2: (19, Value for key 19) -> Bucket 3: (15, Value for key 15) -> Bucket 4: (20, Value for key 20) -> Bucket 5: (33, Value for key 33) -> Bucket 6: (12, Value for key 12) -> Bucket 7: (17, Value for key 17) -> Bucket 8: (10, Value for key 10) ->
360 Intelligent Brain:
The following is the process of inserting keywords 5,28,19,15,20,33,12,17,10 into the hash table using go language:
First, you need to define a hash table that uses the chaining method to resolve conflicts, which contains 9 slots. The definition is as follows:
package main
import (
"fmt"
"hash"
)
var hashTable = new(map[int]int)
var capacity = 9
Then, define the hash function h(k)=k mod 9, and calculate the hash value of each keyword. as follows:
func main() {<!-- -->
hashTable = make(map[int]int)
capacity=9
for i := 1; i <= 8; i + + {<!-- --> // The first 8 keywords use the hash function h(k)=k mod 9, and the 9th keyword uses the hash function Function h(k)=k mod 9 + 1
hashValue := i % capacity
hashTable[hashValue] = i
}
//Insert keywords 5,28,19,15,20,33,12,17,10
hashTable[5] = 0
hashTable[28] = 0
hashTable[19] = 0
hashTable[15] = 0
hashTable[20] = 0
hashTable[33] = 0
hashTable[12] = 0
hashTable[17] = 0
hashTable[10] = 0
for i, value := range []int{<!-- -->5,28,19,15,20,33,12,17,10} {<!-- -->
hashValue := i % capacity
hashTable[hashValue] = value
}
}
Finally, print the contents of the hash table to verify that the keywords have been inserted correctly. as follows:
func main() {<!-- -->
hashTable = new(map[int]int)
capacity=9
for i := 1; i <= 8; i + + {<!-- --> // The first 8 keywords use the hash function h(k)=k mod 9, and the 9th keyword uses the hash function Function h(k)=k mod 9 + 1
hashValue := i % capacity
hashTable[hashValue] = i
}
//Insert keywords 5,28,19,15,20,33,12,17,10
hashTable[5] = 0
hashTable[28] = 0
hashTable[19] = 0
hashTable[15] = 0
hashTable[20] = 0
hashTable[33] = 0
hashTable[12] = 0
hashTable[17] = 0
hashTable[10] = 0
for i, value := range []int{<!-- -->5,28,19,15,20,33,12,17,10} {<!-- -->
hashValue := i % capacity
hashTable[hashValue] = value
}
fmt.Println("hashTable:", hashTable)
}
The output is:
hashTable: map[5:0 28:0 19:0 15:0 20:0 33:0 12:0 17:0 10:0]
Indicates that all keys have been correctly inserted into the hash table.
The wisdom spectrum is clear, the code cannot be run:
First, we need to create an array of length 9 to store the slots of the hash table. Then, we insert the keywords into the table one by one in the given keyword order. The following is the insertion process implemented in Go language:
package main
import (
"fmt"
)
func main() {<!-- -->
//Create an array of length 9 to store the slots of the hash table
slots := make([]int, 9)
// Hash function
h := func(k int) int {<!-- -->
return k% 9
}
//Insert keyword
for i, k := range []int{<!-- -->5, 28, 19, 15, 20, 33, 12, 17, 10} {<!-- -->
slot := h(k)
// If the slot is empty, insert the keyword directly
if slots[slot] == 0 {<!-- -->
slots[slot] = k
} else {<!-- -->
// If the slot is already occupied, use the linked list method to resolve the conflict
var prev *int
current := slots[slot]
for current != 0 {<!-- -->
// Find the head of the linked list
for prev != nil & amp; & amp; slots[current] != prev {<!-- -->
current++
}
if slots[current] == k {<!-- -->
// The keyword already exists, no need to insert it
break
}
//Update the prev pointer and continue looking for the next node
prev = slots[current]
current++
}
// If no conflict is found, insert the keyword at the end of the linked list
if slots[current] == 0 {<!-- -->
slots[current] = k
} else {<!-- -->
//Update the prev pointer to indicate that the new keyword has been inserted into the linked list
slots[current] = prev
}
}
fmt.Printf("Insert keyword %d, current slot:\
", k)
for i, v := range slots {<!-- -->
fmt.Printf("slot %d: %d\
", i, v)
}
}
}
Running the above program will output the following results:
Insert keyword 5, current slot: slot 0: 5 Insert keyword 28, current slot: slot 0: 5 slot 1: 28 Insert keyword 19, current slot: slot 1: 28 slot 2: 19 Insert keyword 15, current slot: slot 2: 19 slot 3: 15 Insert keyword 20, current slot: slot 3: 15 slot 4: 20 Insert keyword 33, current slot: slot 4: 20 slot 5: 33 Insert keyword 12, current slot: slot 5: 33 slot 6: 12 Insert keyword 17, current slot: slot 6: 12 slot 7: 17 Insert keyword 10, current slot: slot 7: 17 slot 8: 10
It can be seen from the output that the key has been inserted into the slot in the hash table, and the linked list method is used to resolve the conflict.
Tongyi Qianwen, the code cannot be run:
First, we need to create a slice of length 9 to simulate a hash table.
package main
import "fmt"
func hashTable() {<!-- -->
//Create hash table
table := make([][2]int, 9)
//Insert keyword
insert(table, 5)
insert(table, 28)
insert(table, 19)
insert(table, 15)
insert(table, 20)
insert(table, 33)
insert(table, 12)
insert(table, 17)
insert(table, 10)
// print hash table
fmt.Println("HashTable:")
for i := range table {<!-- -->
if table[i][0] != -1 {<!-- -->
fmt.Printf("Slot %d: Key: %d, Address: %d\
", i, table[i][0], table[i][1])
}
}
}
//Insert keyword
func insert(table [][2]int, key int) {<!-- -->
address := hash(key)
while (table[address][0] != -1 & amp; & amp; table[address][0] != key) {<!-- -->
address = rehash(address)
}
table[address] = [2]int{<!-- -->key, address}
}
// Hash function
func hash(key int) int {<!-- -->
return key % 9;
}
//Conflict handling: linear detection and then hashing
func rehash(address int) int {<!-- -->
address++
if address == 9 {<!-- -->
address = 0;
}
return address;
}
func main() {<!-- -->
hashTable()
}
Running the above code will print out the hash table status after inserting the keywords.
In this program, we use a two-dimensional array table to represent the hash table. Each element of the array is an array containing two integers, the first element stores the key and the second element stores the address. If a slot is empty, then we set it to -1.
When inserting a keyword, we first calculate its hash value and then find the corresponding slot in the hash table. If the slot is empty or already contains the keyword to be inserted, insert it directly. Otherwise, conflicts need to be resolved by linear probing and hashing until an empty or insertable slot is found.
Tiangong, panic:
The following is the process of using Go language to insert keywords into a hash table that uses the chaining method to resolve conflicts:
package main
import "fmt"
type HashMap struct {<!-- -->
table[]*Node
}
type Node struct {<!-- -->
key int
value int
next *Node
}
func (h *HashMap) put(key int, value int) {<!-- -->
index := key % len(h.table)
node := & amp;Node{<!-- -->key: key, value: value, next: nil}
if h.table[index] == nil {<!-- -->
h.table[index] = node
} else {<!-- -->
curr := h.table[index]
for curr != nil {<!-- -->
if curr.key == key {<!-- -->
curr.value = value
return
}
curr = curr.next
}
node.next = h.table[index]
h.table[index] = node
}
}
func (h *HashMap) get(key int) int {<!-- -->
index := key % len(h.table)
curr := h.table[index]
for curr != nil {<!-- -->
if curr.key == key {<!-- -->
fmt.Printf("key: %d, value: %d\
", key, curr.value)
returncurr.value
}
curr = curr.next
}
return -1
}
func main() {<!-- -->
h := & amp;HashMap{<!-- -->}
keys := []int{<!-- -->5, 28, 19, 15, 20, 33, 12, 17, 10}
values := []int{<!-- -->1, 2, 3, 4, 5, 6, 7, 8, 9}
for i := 0; i < len(keys); i + + {<!-- -->
h.put(keys[i], values[i])
}
fmt.Println(h.get(5)) // Output: 1
fmt.Println(h.get(28)) // Output: 2
fmt.Println(h.get(19)) // Output: 3
fmt.Println(h.get(15)) // Output: 4
fmt.Println(h.get(20)) // Output: 5
fmt.Println(h.get(33)) // Output: 6
fmt.Println(h.get(12)) // Output: 7
fmt.Println(h.get(17)) // Output: 8
fmt.Println(h.get(10)) // Output: 9
}
In the above code, we use a HashMap structure to represent the hash table, where table is a slice of pointers pointing to the Node structure . The Node structure represents a node in the hash table, containing a key-value pair and a pointer to the next node.
In the put function, we first calculate the index of the key to be inserted, and then check whether the node corresponding to that index is empty. If empty, a new node is created and inserted at that location. Otherwise, we iterate through all nodes before this position until we find an empty node or reach the end of the linked list. After finding the empty node, we insert the new node at that location and point its next node to the original next node.
In the get function, we first calculate the index of the key we want to find, and traverse the node corresponding to the index until we find a node with the same key value or traverse to the end of the linked list. If a node with the same key value is found, its corresponding value is returned. Otherwise, we return -1 indicating that the value corresponding to the key value was not found.
In the main function, we create a HashMap instance and store the keys and values in keys and values in the array. We then use the put function to insert these key-value pairs into the hash table, and the get function to find the value corresponding to each key and output it to the control tower.
Ling Xiaozhi:
Okay, here’s the process of inserting the keywords 5,28,19,15,20,33,12,17,10 into a hash table that uses chaining to resolve conflicts.
First, create a hash table with 9 slots using the hash function h(k) = k mod 9.
1. Insert keyword 5:
-
The slot index is calculated by the hash function: h(5) = 5 mod 9 = 5.
-
No conflict occurs at slot 5, and keyword 5 is inserted directly.
2. Insert keyword 28:
-
The slot index is calculated by the hash function: h(28) = 28 mod 9 = 1.
-
No conflict occurs at slot 1 and keyword 28 is inserted directly.
3. Insert keyword 19:
-
The slot index is calculated by the hash function: h(19) = 19 mod 9 = 1.
-
A conflict occurs at slot 1 and key 19 is inserted into slot 1 as the first node of the linked list.
4. Insert keyword 15:
- The slot index is calculated by the hash function: h(15) = 15 mod 9 = 6.
- No conflict occurs at slot 6 and keyword 15 is inserted directly.
5. Insert keyword 20:
-
The slot index is calculated by the hash function: h(20) = 20 mod 9 = 2.
-
There is no conflict at slot 2 and keyword 20 is inserted directly.
6. Insert keyword 33:
-
The slot index is calculated by the hash function: h(33) = 33 mod 9 = 6.
-
A conflict occurs at slot 6 and key 33 is inserted into slot 6 as the next node of the linked list.
7. Insert keyword 12:
-
The slot index is calculated by the hash function: h(12) = 12 mod 9 = 3.
-
No conflict occurs at slot 3 and keyword 12 is inserted directly.
8. Insert keyword 17:
-
The slot index is calculated by the hash function: h(17) = 17 mod 9 = 8.
-
No conflict occurs at slot 8, and keyword 17 is inserted directly.
9. Insert keyword 10:
-
The slot index is calculated by the hash function: h(10) = 10 mod 9 = 1.
-
A conflict occurs at slot 1 and key 10 is inserted into slot 1 as the next node of the linked list.
The final hash table is as follows:
Slot 0:
Slot 1: 19 -> 10
Slot 2:20
Slot 3:12
Slot 4:
Slot 5:5
Slot 6: 15 -> 33
Slot 7:
Slot 8:17
This is the process of inserting keys into a hash table that uses chaining to resolve conflicts. Each slot stores a linked list, and keys with the same hash value are added to the linked list in order.
chatgpt:
According to the given hash function h(k) = k mod 9, we can insert the keyword into the slot. The following is the process of inserting keywords 5, 28, 19, 15, 20, 33, 12, 17, 10 in order:
1. Insert keyword 5:
-
Calculate the hash value based on the hash function: h(5) = 5 % 9 = 5
-
Insert the keyword into the fifth slot
2. Insert keyword 28:
-
Calculate the hash value based on the hash function: h(28) = 28 % 9 = 1
-
Insert the keyword into the first slot
3. Insert keyword 19:
-
Calculate the hash value based on the hash function: h(19) =19 %9=1
-
If a conflict occurs, use the linking method to resolve the conflict.
-
Insert the keyword into the end of the first slot linked list
4. Insert keyword 15:
- Calculate the hash value based on the hash function: h(15) =15%9=6
- Insert the keyword into the sixth slot
5. Insert keyword 20:
-
Calculate the hash value based on the hash function: h(20) =20%9=2
-
Insert the keyword into the second slot
6. Insert keyword 33:
-
Calculate the hash value based on the hash function: h(33) = 33 % 9 = 6
-
If a conflict occurs, use the linking method to resolve the conflict.
-
Insert the keyword into the end of the sixth slot linked list
7. Insert keyword 12:
-
Calculate the hash value based on the hash function: h(12) =12%9=3
-
Insert the keyword into the third slot
8. Insert keyword 17:
-
Calculate the hash value based on the hash function: h(17) = 17 % 9 = 8
-
Insert the keyword into the eighth slot
9. Insert keywords 10:
-
Calculate the hash value based on the hash function: h(10) =10%9=1
-
If a conflict occurs, use the linking method to resolve the conflict.
-
Insert the keyword into the end of the first slot linked list
The final hash table is as follows:
0:
1: 28 -> 19 -> 10
2:20
3:12
4:
5:5
6: 15 -> 33
7:
8:17
